Boolean expression simplification Exercise 3 solution

!((x < y) && (r >= s))
!(x < y) || !(r >= s)
x >= y || r < s

De Morgan’s Law results in the and (&&) becoming or (||) when the not (!) is distributed over it.

The opposite of less tha (<) is greater than or equal to (>=). The opposite of >= is <.

A common mistake is assuming that the opposite of greater than (>) is less than (<).

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